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Question

Question: Equation of the line passing through (1, 2) and parallel to the line \(y = 3 x - 1\)is....

Equation of the line passing through (1, 2) and parallel to the line y=3x1y = 3 x - 1is.

A

y+2=x+1y + 2 = x + 1

B

y+2=3(x+1)y + 2 = 3 ( x + 1 )

C

y2=3(x1)y - 2 = 3 ( x - 1 )

D

y2=x1y - 2 = x - 1

Answer

y2=3(x1)y - 2 = 3 ( x - 1 )

Explanation

Solution

The required equation which passes through (1, 2) and its gradient is m=3m = 3 , is (y2)=3(x1)( y - 2 ) = 3 ( x - 1 ) .