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Question: Equation of the line of projection of the line 3x - y + 2z -1 = 0 = x + 2y - z - 2 on the plane 3x +...

Equation of the line of projection of the line 3x - y + 2z -1 = 0 = x + 2y - z - 2 on the plane 3x + 2y +z = 0

Answer

3x + 2y + z = 0, 3x - 8y + 7z + 4 = 0

Explanation

Solution

The line of projection of a line L onto a plane P is the intersection of P and the plane (P') containing L and perpendicular to P. The plane P' is found by taking the general equation of a plane containing L (P1+λP2=0P_1 + \lambda P_2 = 0) and using the condition that its normal vector is orthogonal to the normal vector of P, solving for λ\lambda. Substituting λ\lambda back gives P'. The line of projection is then expressed as the system of equations for P and P'.