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Question: Equation of the diameter of the circle x<sup>2</sup> + y<sup>2</sup> – 6x + 2y = 0 which passes thro...

Equation of the diameter of the circle x2 + y2 – 6x + 2y = 0 which passes through the origin is –

A

x + 3y = 0

B

x – 3y = 0

C

3x + y = 0

D

3x – y = 0

Answer

x + 3y = 0

Explanation

Solution

Diameter ¼O;kl½ y = mx

passes through centre (3, –1)

Ž – 1 = 3m Ž m = 13- \frac { 1 } { 3 }

Equation y =