Question
Question: Equation of the diameter of the circle x<sup>2</sup> + y<sup>2</sup> – 6x + 2y = 0 which passes thro...
Equation of the diameter of the circle x2 + y2 – 6x + 2y = 0 which passes through the origin is –
A
x + 3y = 0
B
x – 3y = 0
C
3x + y = 0
D
3x – y = 0
Answer
x + 3y = 0
Explanation
Solution
Diameter ¼O;kl½ y = mx
passes through centre (3, –1)
Ž – 1 = 3m Ž m = −31
Equation y =