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Question: Equation of the chord of the hyperbola 25x<sup>2</sup> – 16y<sup>2</sup> = 400 which is bisected at ...

Equation of the chord of the hyperbola 25x2 – 16y2 = 400 which is bisected at the point (6, 2), is-

A

16x – 75y = 418

B

75x – 16y = 418

C

25x – 4y = 400

D

None of these

Answer

75x – 16y = 418

Explanation

Solution

Equation of hyperbola is 25x2 – 16y2 = 400

Ž x216\frac{x^{2}}{16}y225\frac{y^{2}}{25} = 1

Chord is bisected at (6, 2)

\ 6x162y25=62162225\frac{6x}{16} - \frac{2y}{25} = \frac{6^{2}}{16} - \frac{2^{2}}{25}

Ž 75x – 16y = 418.