Question
Question: Equation of the chord of the hyperbola 25x<sup>2</sup> – 16y<sup>2</sup> = 400 which is bisected at ...
Equation of the chord of the hyperbola 25x2 – 16y2 = 400 which is bisected at the point (6, 2), is-
A
16x – 75y = 418
B
75x – 16y = 418
C
25x – 4y = 400
D
None of these
Answer
75x – 16y = 418
Explanation
Solution
Equation of hyperbola is 25x2 – 16y2 = 400
Ž 16x2 – 25y2 = 1
Chord is bisected at (6, 2)
\ 166x−252y=1662−2522
Ž 75x – 16y = 418.