Equation of tangent to curve y = | x2 – 13x + 40 | at pointe... | MATH - DIFFERENTIATION OF IMPLICIT FUNCTION, PARAMETRIC AND COMPOSITE FUNCTIONS | SolveeIt | Solveeit

Today, August 19

Question

Equation of tangent to curve y = | x² – 13x + 40 | at point

x = 6 is

A

x + y + 4 = 0

B

x – y – 4 = 0

C

x + y = 4

D

x – y + 4 = 0

Answer

x – y – 4 = 0

Explanation

Solution

Near x = 6 ; f(x) = – x² + 13x – 40

f ′(x) = – 2x + 13 ∴ f(6) = – 1