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Question: Equation of motion in the same direction is given by y<sub>1</sub> = A sin(wt – kx), y<sub>2</sub> =...

Equation of motion in the same direction is given by y1 = A sin(wt – kx), y2 = A sin(wt – kx – q). The amplitude of the medium particle will be –

A

2A cosθ2\frac{\theta}{2}

B

2A cosq

C

2\sqrt{2}A cosθ2\frac{\theta}{2}

D

2\sqrt{2}A cos q

Answer

2A cosθ2\frac{\theta}{2}

Explanation

Solution

A = = 2a2(1+cos⁡θ)\sqrt { 2 a ^ { 2 } ( 1 + \cos \theta ) }

= 2 A cos q/2