Question
Mathematics Question on Straight lines
Equation of line passing through the point (1,2) and perpendicular to the line y=3x−1 is
A
x+3y−7=0
B
x+3y+7=0
C
x+3y=0
D
x−3y=0
Answer
x+3y−7=0
Explanation
Solution
Given line is
y=3x−1
∴ Slope of the given line =3
∴ Slope of a line perpendicular to the given line =−31
∴ Equation of required line will be
y−2=3−1(x−1)
⇒3y−6=−x+1
⇒x+3y−7=0