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Question

Mathematics Question on Straight lines

Equation of line passing through the point (1,2)(1,2) and perpendicular to the line y=3x1y = 3x -1 is

A

x+3y7=0x + 3y - 7 = 0

B

x+3y+7=0x + 3y + 7 = 0

C

x+3y=0x + 3y = 0

D

x3y=0x - 3y = 0

Answer

x+3y7=0x + 3y - 7 = 0

Explanation

Solution

Given line is
y=3x1y=3 x-1
\therefore Slope of the given line =3=3
\therefore Slope of a line perpendicular to the given line =13=-\frac{1}{3}
\therefore Equation of required line will be
y2=13(x1)y-2 =\frac{-1}{3}(x-1)
3y6=x+1\Rightarrow 3 y-6 =-x+1
x+3y7=0\Rightarrow x+3 y -7 =0