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Question

Question: Equation of line passing through (1, 2) and perpendicular to \(3 x + 4 y + 5 = 0\) is....

Equation of line passing through (1, 2) and

perpendicular to 3x+4y+5=03 x + 4 y + 5 = 0 is.

A

3y=4x23 y = 4 x - 2

B

3y=4x+33 y = 4 x + 3

C

3y=4x+43 y = 4 x + 4

D

3y=4x+23 y = 4 x + 2

Answer

3y=4x+23 y = 4 x + 2

Explanation

Solution

Trick : Line 3y=4x+23 y = 4 x + 2is perpendicular to given line and passing through (1, 2).