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Question: Equation of curve through (2, 2) satisfying (1– x<sup>2</sup>) \(\frac{dy}{dx}\)+ xy = 5x is...

Equation of curve through (2, 2) satisfying

(1– x2) dydx\frac{dy}{dx}+ xy = 5x is

A

(x–5)2 + 3 (1–y2) = 0

B

(y–5)2 + (1–x2) = 3

C

(y–5)2 + 3(1–x2) = 0

D

(1–x2) + 3(y–5)2 = 0

Answer

(y–5)2 + 3(1–x2) = 0

Explanation

Solution

dydx+x1x2y=5x1x2\frac{dy}{dx} + \frac{x}{1 - x^{2}}y = \frac{5x}{1 - x^{2}}whose solution is

y.ex21x2dx=(5x1x2)y.e^{\int_{}^{}{\frac{x^{2}}{1 - x^{2}}dx}} = \int_{}^{}\left( \frac{5x}{1 - x^{2}} \right)I.F. dx + c