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Question

Question: Equation of Boyle's law is....

Equation of Boyle's law is.

A

dPp=dVV\frac { d P } { p } = - \frac { d V } { V }

B

dPP=+dVV\frac { d P } { P } = + \frac { d V } { V }

C

d2PP=dVdT\frac { d ^ { 2 } P } { P } = - \frac { d V } { d T }

D

d2PP=+d2VdT\frac { d ^ { 2 } P } { P } = + \frac { d ^ { 2 } V } { d T }

Answer

dPp=dVV\frac { d P } { p } = - \frac { d V } { V }

Explanation

Solution

Boyle's law PV- P V= constant

On differentiating the equation,

d(PV)=d(C)d ( P V ) = d ( C )PdV+VdP=0P d V + V d P = 0

VdP=PdVV d P = - P d VdPP=dVV\frac { d P } { P } = - \frac { d V } { V }.