Question

Equation of a line passing through the point of intersection of lines $2 x - 3 y + 4 = 0$, $3 x + 4 y - 5 = 0$ and perpendicular to $6 x - 7 y + 3 = 0$ , then its equation is

• A. $119 x + 102 y + 125 = 0$
• B. $119 x + 102 y = 125$
• C. $119 x - 102 y = 125$
• D. None of these

Answer 1

Answer: (B)

$119 x + 102 y = 125$

Answer 2

The point of intersection of the lines $2 x - 3 y + 4 = 0$ and $\left( \frac { - 1 } { 17 } , \frac { 22 } { 17 } \right)$

The slope of required line = $\frac { - 7 } { 6 }$ .

Hence, Equation of required line is, $y - \frac { 22 } { 7 } = \frac { - 7 } { 6 } \left( x + \frac { 2 } { 34 } \right)$

⇒ $119 x + 102 y = 125$ .