Solveeit Logo

Question

Question: Equation of a gas is given by (T<sup>7</sup>/P<sup>2</sup>)<sup>1/5</sup> = constant. Coefficient of...

Equation of a gas is given by (T7/P2)1/5 = constant. Coefficient of volume expansion of that gas in isobaric process is –

A

1T- \frac{1}{T}

B

1.5T- \frac{1.5}{T}

C

2.5T- \frac{2.5}{T}

D

3.5T- \frac{3.5}{T}

Answer

2.5T- \frac{2.5}{T}

Explanation

Solution

P25P^{- \frac{2}{5}}= C ; (nRTV)25\left( \frac{nRT}{V} \right)^{- \frac{2}{5}}= C

T7525T^{\frac{7}{5} - \frac{2}{5}} V25V^{\frac{2}{5}}= C ; TV25TV^{\frac{2}{5}}= C

ln T + 25\frac{2}{5}ln V = ln C

ΔTT\frac{\Delta T}{T}+25\frac { 2 } { 5 } ΔVV\frac{\Delta V}{V}= 0 ; 52T- \frac{5}{2T} = ΔVVΔT\frac{\Delta V}{V\Delta T} = g

g = – 2.5T\frac{2.5}{T}