Question

Equation of a gas in terms of pressure (P), absolute temperature, (T) and density (rf) is:

• A. $\frac{{{P}_{1}}}{{{T}_{1}}{{d}_{1}}}=\frac{{{P}_{2}}}{{{T}_{2}}{{d}_{2}}}$
• B. $\frac{{{P}_{1}}{{T}_{1}}}{{{d}_{1}}}=\frac{{{P}_{2}}{{d}_{1}}}{{{d}_{2}}}$
• C. $\frac{{{P}_{1}}{{d}_{2}}}{{{T}_{2}}}=\frac{{{P}_{2}}{{d}_{1}}}{{{T}_{1}}}$
• D. $\frac{{{P}_{1}}{{d}_{1}}}{{{T}_{1}}}=\frac{{{P}_{1}}{{d}_{2}}}{{{T}_{2}}}$

Answer 1

Answer: (A)

$\frac{{{P}_{1}}}{{{T}_{1}}{{d}_{1}}}=\frac{{{P}_{2}}}{{{T}_{2}}{{d}_{2}}}$

Answer 2

Gas equation is $\frac{PV}{T}=cons\tan t=R$ or $\frac{{{P}_{1}}{{V}_{1}}}{{{T}_{1}}}=\frac{{{P}_{2}}{{V}_{2}}}{{{T}_{2}}}$ If m is the mass of a gas and ${{d}_{1}}$ and ${{d}_{2}}$ are its density at absolute temperature ${{T}_{1}}K$ and ${{T}_{2}}K,$ then ${{V}_{1}}=m/{{d}_{1}}$ and ${{V}_{2}}=m/{{d}_{2}}$ $\therefore$ $\frac{{{P}_{1}}}{{{T}_{1}}}\left ( \frac{m}{{{d}_{1}}} \right)=\frac{{{P}_{2}}}{{{T}_{2}}}\left( \frac{m}{{{d}_{2}}} \right)$ $\frac{{{P}_{1}}}{{{T}_{1}}{{d}_{1}}}=\frac{{{P}_{2}}}{{{T}_{2}}{{d}_{2}}}$