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Question

Question: Equation of a circle whose centre is origin and radius is equal to the distance between the lines \(...

Equation of a circle whose centre is origin and radius is equal to the distance between the lines x=1x = 1 and x=1x = - 1 is.

A

x2+y2=1x ^ { 2 } + y ^ { 2 } = 1

B

x2+y2=2x ^ { 2 } + y ^ { 2 } = \sqrt { 2 }

C

x2+y2=4x ^ { 2 } + y ^ { 2 } = 4

D

x2+y2=4x ^ { 2 } + y ^ { 2 } = - 4

Answer

x2+y2=4x ^ { 2 } + y ^ { 2 } = 4

Explanation

Solution

Radius = 2, C (0, 0)

Equation of circle can be found from this.