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Question: Equation: \[2x - y = 4\] meets \[x\] axis at \[( - 4,0)\] \[y\] axis at \[(0,2)\] \[x\] axis...

Equation: 2xy=42x - y = 4 meets
xx axis at (4,0)( - 4,0)
yy axis at (0,2)(0,2)
xx axis at (2,0)(2,0)
yy axis at (0,4)(0, - 4)

Explanation

Solution

Here, we have to find the values of xx co-ordinate and yy co-ordinate where the given line meets the xx axis and yy axis. We have to find those co-ordinates by using the intercept concept. The point where a curve or a line crosses the axis of the graph is called an intercept. If a point crosses the xx-axis, then it is said to be xx-intercept and if a point crosses the yy-axis, then it is known as yy-intercept.

Complete step-by-step answer:
The Equation 2xy=42x - y = 4 is an equation of a straight line. The equation of a straight line is of the form y=mx+cy = mx + c where mm is the slope or the gradient and cc is the yy -intercept.
Now, we will find the xx - intercept.
Substituting y=0y = 0 in the above equation, we get
2x0=4\Rightarrow 2x - 0 = 4
2x=4\Rightarrow 2x = 4
Dividing both the sides by 2, we get
x=2\Rightarrow x = 2
So, the equation meets the xx - axis at x=2x = 2
Now, we have to find the yy - intercept.
Substituting x=0x = 0 and solving for yy , we have
2(0)y=4\Rightarrow 2(0) - y = 4
y=4\Rightarrow - y = 4
Rewriting the equation, we get
y=4\Rightarrow y = - 4
So, the equation meets the yy - axis at y=4y = - 4
Therefore, the equation 2xy=42x - y = 4 meets the xx - axis at (2,0)\left( {2,0} \right) and the yy - axis at (0,4)\left( {0, - 4} \right) .

Note: We can find the yy - intercept from the equation 2xy=42x - y = 4. Rewriting the equation as y=2x4y = 2x - 4 . Since the equation of a straight line is of the form y=mx+cy = mx + c where mm is the slope or the gradient and cc is the yy -intercept. The slope of a line is defined as the ratio of the amount that yy increases as xx increases some amount. Slope tells us how steep a line is, or how much yy increases as xx increases. We will get the xx-intercept as y=4y = - 4.