Question

Equal weight of 'X' (At. wt. = 36) and 'Y' (At. wt. = 24) are reacted to form the compound X2Y3. Then :

• A. X is the limiting reagent
• B. Y is the limiting reagent
• C. No reactant is left over and mass of X2Y3 formed is double the mass of ‘X’ taken
• D. None of these

Answer 1

Answer: (C)

No reactant is left over and mass of X2Y3 formed is double the mass of ‘X’ taken

Answer 2

2 X + 3 Y $\longrightarrow$ X2Y3

weight W gram W gram 0

Mole $\frac{w}{36}$ $\frac{w}{24}$

L.R. $\rightarrow$ $\frac{w}{36}$ ×$\frac{1}{2}$ $\frac{w}{24 \times 3}$

No. one is L.R. $\frac{1}{72}$ $\frac{1}{72}$

2 X + 3Y $\longrightarrow$ X2Y3

$\frac { w } { 36 }$ $\frac { w } { 24 }$

$\frac{w}{2\lbrack 36\rbrack}$

weight of X2Y3 = $\frac{w}{2 \times 36}$ [72 × 2] = 2 w

So weight of X2Y3 = 2 [weight of X Taken ]