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Question: Equal potentials are applied on an iron and copper wire of same length. In order to have same curren...

Equal potentials are applied on an iron and copper wire of same length. In order to have same current flow in the wire, the ratio (rironrcopper)\left( \frac{r_{iron}}{r_{copper}} \right) of their radii must be [Given that specific resistance of iron = 1.0 × 10–7m and that of

copper = 1.7 × 10–8m]

A

About 1.2

B

About 2.4

C

About 3.6

D

About 4.8

Answer

About 2.4

Explanation

Solution

V = constant., i = constant. So R = constant

PiliAi=ρCulCuACuρiliri2=ρCulCurCu2\frac{P_{i}l_{i}}{A_{i}} = \frac{\rho_{Cu}l_{Cu}}{A_{Cu}} \Rightarrow \frac{\rho_{i}l_{i}}{r_{i}^{2}} = \frac{\rho_{Cu}l_{Cu}}{r_{Cu}^{2}}

rirCu=ρiρCu=1.0×1071.7×108=100172.4\frac{r_{i}}{r_{Cu}} = \sqrt{\frac{\rho_{i}}{\rho_{Cu}}} = \sqrt{\frac{1.0 \times 10^{- 7}}{1.7 \times 10^{- 8}}} = \sqrt{\frac{100}{17}} \approx 2.4