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Question: The decomposition of CaCO3 in a closed vessel is represented by the equation CaCO3 ⇌ (s) CaO (s) ...

The decomposition of CaCO3 in a closed vessel is represented by the equation
CaCO3 ⇌ (s) CaO (s) + CO2 (g)
Calculate the number of phases, components and degree of freedom

A

p = 2: C=3; F = 3

B

p = 3; C=2; F = 1

C

p = 2: C=2; F = 2

D

p = 3: C=3; F = 2

Answer

p = 3; C=2; F = 1

Explanation

Solution

The decomposition of calcium carbonate is represented by the equilibrium: CaCO3(s)CaO(s)+CO2(g)\text{CaCO}_3\text{(s)} \rightleftharpoons \text{CaO(s)} + \text{CO}_2\text{(g)}

  1. Phases (p): There are three physically distinct and separable parts: solid CaCO3_3, solid CaO, and gaseous CO2_2. Thus, p=3p=3.
  2. Components (C): There are three chemical species (CaCO3_3, CaO, CO2_2) involved in one independent equilibrium reaction. The number of components is calculated as C=(number of species)(number of independent reactions)=31=2C = (\text{number of species}) - (\text{number of independent reactions}) = 3 - 1 = 2.
  3. Degrees of Freedom (F): Using the Gibbs Phase Rule, F=CP+2F = C - P + 2. Substituting the values, F=23+2=1F = 2 - 3 + 2 = 1.