Question

$E^{o}$values of some redox couples are given below. On the basis of these values choose the correct option.

$E^{o}$values:,$Fe^{3 +}/Fe^{2 +} = + 0.77;I_{2}/I^{-} = + 0.54;$

$Cu^{2 +}/Cu = + 0.34;Ag^{+}/ag = + 0.80V$

• A. Cu will reduce $Br^{-}$
• B. Cu will reduce Ag
• C. Cu will reduce $I^{-}$
• D. Cu will reduce $Br_{2}$

Answer 1

Answer: (D)

Cu will reduce $Br_{2}$

Answer 2

: More positive the value of $E^{o}$ greater is the tendency of the species to get reduced. On the basis of the given $E^{o}$ values, $Br_{2}$ is having highest $E^{o}$value $( + 1.90)$ hence, Cu will easily reduce $Br_{2}$