Solveeit Logo

Question

Question: Enthalpy of polymerisation of ethylene, as represented by the reaction, nCH2=CH2\(\longrightarrow\) ...

Enthalpy of polymerisation of ethylene, as represented by the reaction, nCH2=CH2\longrightarrow (-CH2-CH2-)n is -100 kJ per mole of ethylene. Given bond enthalpy of C=C bond is 600 kJ mol-1, enthalpy of C-C bond (in kJ mol) will be :

A

116.7

B

350

C

700

D

Indeterminate

Answer

350

Explanation

Solution

nCH2 = CH2 \longrightarrow (– CH2 – CH2 –)n Δ\DeltaH = – 100 KJ/mole

Double bond of ethylene converted to two single bonds.

Δ\DeltaH = – 100 = B.E.C=C – 2 B.E.C–C

\Rightarrow– 100 = 600 – 2 ´ B.E.C–C \RightarrowB.E.C–C = 350 KJ/mole