Question
Question: Enthalpy of neutralization of strong acid and strong base forming \[3mol\] of water (A) \[ - 57.6K...
Enthalpy of neutralization of strong acid and strong base forming 3mol of water
(A) −57.6KJ
(B) 3−57.6KJ
(C) −57.6×3KJ
(D) −57.6×6KJ
Solution
Enthalpy of neutralization term related to thermodynamics. Thermodynamics deals with the heat (is a form of energy) and one form of energy is converted to another form of energy and study about different forms of energy.
Complete step by step answer:
Enthalpy of neutralization may be defined as the heat released when an acid reacts with a base to form a salt with small other products like water. During Enthalpy of neutralization when reaction takes place between one equivalent of acid and one equivalent of base react with each other energy is released. So this type of reaction is also called an exothermic reaction.
On the basis of speed of released H+ in aqueous medium acids are two types-(1) Strong acid- An acid which gives H+ very fastly in aqueous medium like sulphuric acid(H2SO4).
(2) Weak acid- An acid which gives H+ very slowly in aqueous medium like ethanoic acid CH3COOH.
On the basis of speed of released OH− in aqueous medium acids are two types-(1) Strong base- An acid which gives OH− very fastly in aqueous medium like Caustic soda (NaOH).
(2) Weak base- An acid which gives OH− very slowly in aqueous medium like ammonium hydroxide (NH4OH).
Amount of energy released during reaction depends on what type of acid and base react with each other. When a strong acid and strong base react with each other to form a salt and form 1mol of water and release energy −57.6KJ.
So producing 3mol of water molecules the energy of neutralization is −57.6KJ×3.
Hence option C is the correct option.
Note:
-The Enthalpy of neutralization is denoted by ΔHn.
-The Enthalpy of neutralization is always negative because energy is always released in the surrounding.
-The amount of energy released depends upon the type of acid and base react with each other.