Question

Enthalpy of CH4+$\frac{1}{2}$O2$\rightarrow$CH3OH is negative. If enthalpy of combustion of CH4 and CH3OH are x and y respectively. Then which relation is correct : -

• A. x>y
• B. x<y
• C. x=y
• D. x$\geq$y

Answer 1

Answer: (B)

x<y

Answer 2

The correct option is (B): x < y.
CH4 +$\frac{1}{2}$ O2 $\rightarrow$ CH3OH
$\triangle$H = x – y
Given, $\triangle$H = – ve
Hence, $x – y < 0 \space x < y$ .