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Question

Physics Question on Motion in a straight line

Energy required to accelerate a car from 10m/s10 \,m / s to 20m/s20\, m / s compared with that required to accelerate it frem 00 to 10m/s10 \,m / s is

A

twice

B

thrice

C

four times

D

same

Answer

thrice

Explanation

Solution

KE1=12m(v22v12) K E_{1} =\frac{1}{2} m\left(v_{2}^{2}-v_{1}^{2}\right) KE1=12m[(20)2(10)2]\therefore K E_{1} =\frac{1}{2} m\left[(20)^{2}-(10)^{2}\right] KE1=12m(400100)\Rightarrow K E_{1} =\frac{1}{2} m(400-100) KE1=12m×300=150m \Rightarrow K E_{1} =\frac{1}{2} m \times 300=150\, m ... (i) KE2=12m[(10)20]K E_{2} =\frac{1}{2} m\left[(10)^{2}-0\right] KE2=12m×100=50m\Rightarrow KE _{2}=\frac{1}{2} m \times 100=50 \,m ... (ii) From Eqs. (i) and (ii), we have KE1=3KE2KE _{1}=3 KE _{2}