Question
Question: Energy released in fusion of 1 kg of deuterium nuclei....
Energy released in fusion of 1 kg of deuterium nuclei.
A
8×1013J
B
6×1027J
C
2×107KwH
D
8×1023MeV
Answer
8×1023MeV
Explanation
Solution
Fusion reaction of deuterium is
1H2+1H2→2He3+0n1+3.276muMeV
So E=2×26.02×1023×103×3.27×1.6×10−13=7.8×1013J
=8×1013J.