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Question

Chemistry Question on Structure of atom

Energy of one mole of photons of radiation whose frequency is 5×1014Hz5\times 10^{14}\,Hz is

A

199.51kJmol1199.51\,kJ\,mol^{-1}

B

189.51kJmol1189.51\,kJ\,mol^{-1}

C

198.51kJmol1198.51\,kJ\,mol^{-1}

D

188.51kJmol1188.51\,kJ\,mol^{-1}

Answer

199.51kJmol1199.51\,kJ\,mol^{-1}

Explanation

Solution

\because Energy of 11 photon, R=hvR=h v
\therefore Energy of 11 mole of photon,
E=NAhvE'=N_{A} h v
=6.022×1023×6.626×1034×5×1014=6.022 \times 10^{23} \times 6.626 \times 10^{-34} \times 5 \times 10^{14}
=199.508×103Jmol1=199.508 \times 10^{3} J\,mol ^{-1}