Question

Energy of H-atom in the ground state is –13.6 eV, hence energy in the second excited state is :

• A. – 6.8 Ev
• B. – 3.4 eV
• C. – 1.51 eV
• D. – 4.53 eV

Answer 1

Answer: (C)

– 1.51 eV

Answer 2

2nd excited state will be the 3rd energy level.

$En = \frac{13.6}{n^{2}}eV or E = \frac{13.6}{9} = 1.51eV.$