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Question: Energy of electron of hydrogen atom in second Bohr orbit is...

Energy of electron of hydrogen atom in second Bohr orbit is

A

−5.44×10−19J- 5.44 \times 10^{- 19}J

B

−5.44×10−19kJ- 5.44 \times 10^{- 19}kJ

C

−5.44×10−19cal- 5.44 \times 10^{- 19}cal

D

−5.44×10−19eV- 5.44 \times 10^{- 19}eV

Answer

−5.44×10−19J- 5.44 \times 10^{- 19}J

Explanation

Solution

E=−2.172×10−18n2=−2.172×10−1822E = - \frac{2.172 \times 10^{- 18}}{n^{2}} = \frac{- 2.172 \times 10^{- 18}}{2^{2}}

=−5.42×10−19J= - 5.42 \times 10^{- 19}J.