Question

Energy of a particle is given by E = $\frac{A\sqrt{x}}{B + t}$where A and B are constant and t is in seconds and x is in metre. Then dimension formula of AB is –

• A. ML^3/2 T^–3
• B. ML^3/2
• C. ML²T^–1
• D. ML²T^–2

Answer 1

Answer: (B)

ML^3/2

Answer 2

[B] = [T]

[A] = $\frac{\lbrack E\rbrack\lbrack B + t\rbrack}{\lbrack x^{1/2}\rbrack}$ = $\frac{ML^{2}T^{- 2}T}{L^{1/2}}$= ML^3/2T^–1

[AB] = ML^3/2