Question
Question: Energy needed in breaking a drop of radius R into n drops of radii r is given by...
Energy needed in breaking a drop of radius R into n drops of radii r is given by
A
4πT(nr2−R2)
B
34π(r3n−R2)
C
4πT(R2−nr2)
D
4πT(nr2+R2)
Answer
4πT(nr2−R2)
Explanation
Solution
Energy needed = Increment in surface energy
= (surface energy of n small drops) –
(surface energy of one big drop)