Question
Question: Energy is being emitted from the surface of a black body at 
B

C
527∘C
D

Answer
527∘C
Explanation
Solution
E1E2=(T1T2)4⇒T2=(E1E2)1/4×T1=(16)1/4×(273+127)
⇒ T2 =800 K=527∘C
