Solveeit Logo

Question

Question: Energy is being emitted from the surface of a black body at ![](https://cdn.pureessence.tech/canvas_...

Energy is being emitted from the surface of a black body at temperature at the rate of . Temperature of the black body at which the rate of energy emission is will be

A

B

C

527C527 ^ { \circ } \mathrm { C }

D

Answer

527C527 ^ { \circ } \mathrm { C }

Explanation

Solution

E2E1=(T2T1)4\frac { E _ { 2 } } { E _ { 1 } } = \left( \frac { T _ { 2 } } { T _ { 1 } } \right) ^ { 4 }T2=(E2E1)1/4×T1=(16)1/4×(273+127)T _ { 2 } = \left( \frac { E _ { 2 } } { E _ { 1 } } \right) ^ { 1 / 4 } \times T _ { 1 } = ( 16 ) ^ { 1 / 4 } \times ( 273 + 127 )

⇒ T2 =800 K=527C= 800 \mathrm {~K} = 527 ^ { \circ } \mathrm { C }