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Question

Chemistry Question on Organic Chemistry- Some Basic Principles and Techniques

Empirical formula of a compound is CH2OCH_2O and its molecular mass is 9090, the molecular formula of the compound is

A

C3H6O3C_3H_6O_3

B

C2H4O2C_2H_4O_2

C

C6H12O6C_6H_{12}O_6

D

CH2OCH_2O

Answer

C3H6O3C_3H_6O_3

Explanation

Solution

The empirical formula of compound =CH2O= CH _{2} O Empirical formula mass =(1×12)+(2×1)+(1×16)=30=(1 \times 12)+(2 \times 1)+(1 \times 16)=30 Molecular mass =90=90 ∴n= Molecular mass  Empirical mass =9030=3\therefore n=\frac{\text { Molecular mass }}{\text { Empirical mass }}=\frac{90}{30}=3 and molecular formula =3×CH2O=3 \times CH _{2} O =C3H6O3= C _{3} H _{6} O _{3}