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Question: EMF of a cell whose half cells are given below is \(H_{2}SO_{4}\) \(Pb_{3}O_{4}\)...

EMF of a cell whose half cells are given below is

H2SO4H_{2}SO_{4}

Pb3O4Pb_{3}O_{4}

A

– 2.03 V

B

1.36 V

C

2.7 V

D

2.03 V

Answer

2.7 V

Explanation

Solution

Ecello=Ecathodeo−EanodeE_{\text{cell}}^{o} = E_{\text{cathode}}^{o} - E_{\text{anode}}; Ecello=0.34−(−2.37)E_{\text{cell}}^{o} = 0.34 - ( - 2.37)

Ecello=2.71VE_{\text{cell}}^{o} = 2.71V.