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Question: Elements of a matrix is represented by \({a_{ij}} = \left| {\dfrac{{3i - j}}{2}} \right|\). Find the...

Elements of a matrix is represented by aij=3ij2{a_{ij}} = \left| {\dfrac{{3i - j}}{2}} \right|. Find the 2×22 \times 2 matrix.

Explanation

Solution

First express the 2×22 \times 2 matrix in its standard form\left| {\begin{array}{*{20}{c}} {{a_{11}}}&{{a_{12}}} \\\ {{a_{21}}}&{{a_{22}}} \end{array}} \right|. Then calculate the elements of the matrix using the given formula aij=3ij2{a_{ij}} = \left| {\dfrac{{3i - j}}{2}} \right|.

Complete step-by-step answer:
In mathematics, a matrix (plural matrices) is a rectangular array or table of numbers, symbols, or expressions, arranged in rows and columns. Example of a 2×22 \times 2matrix is \left| {\begin{array}{*{20}{c}} 2&5 \\\ 3&6 \end{array}} \right|.
The size of a matrix is denoted by the number of rows and columns that a matrix contains.
The elements of a matrix is denoted by aij{a_{ij}}, it means that aij{a_{ij}}is the element in the iith row and jjth column.
Here it is mentioned that aij=3ij2{a_{ij}} = \left| {\dfrac{{3i - j}}{2}} \right|
We have to find a 2×22 \times 2 matrix.
So the matrix will be in the form \left| {\begin{array}{*{20}{c}} {{a_{11}}}&{{a_{12}}} \\\ {{a_{21}}}&{{a_{22}}} \end{array}} \right|
Now we have to calculate a11,a12,a21,a22{a_{11,}}{a_{12}},{a_{21}},{a_{22}} respectively.
aij=3ij2{a_{ij}} = \left| {\dfrac{{3i - j}}{2}} \right|
So a11=3×112=22=1{a_{11}} = \left| {\dfrac{{3 \times 1 - 1}}{2}} \right| = \dfrac{2}{2} = 1
Similarly a12=3×122=12{a_{12}} = \left| {\dfrac{{3 \times 1 - 2}}{2}} \right| = \dfrac{1}{2}, a21=3×212=52{a_{21}} = \left| {\dfrac{{3 \times 2 - 1}}{2}} \right| = \dfrac{5}{2} and a22=3×222=42=2{a_{22}} = \left| {\dfrac{{3 \times 2 - 2}}{2}} \right| = \dfrac{4}{2} = 2
So the required 2×22 \times 2 matrix is \left| {\begin{array}{*{20}{c}} {{a_{11}}}&{{a_{12}}} \\\ {{a_{21}}}&{{a_{22}}} \end{array}} \right|
=\left| {\begin{array}{*{20}{c}} {{a_{11}}}&{{a_{12}}} \\\ {{a_{21}}}&{{a_{22}}} \end{array}} \right| = \left| {\begin{array}{*{20}{c}} 1&{\dfrac{1}{2}} \\\ {\dfrac{5}{2}}&2 \end{array}} \right|

The required 2×22 \times 2 matrix is \left| {\begin{array}{*{20}{c}} 1&{\dfrac{1}{2}} \\\ {\dfrac{5}{2}}&2 \end{array}} \right|

Note: We should also remember various information of matrix regarding aij{a_{ij}}
For example: If a matrix is symmetric than we can say that aij=aji{a_{ij}} = {a_{ji}}, whether if the matrix be skew symmetric then aij=aji{a_{ij}} = - {a_{ji}}. For a null matrix aij=0{a_{ij}} = 0.