Question
Question: Elements of a matrix is represented by \({a_{ij}} = \left| {\dfrac{{3i - j}}{2}} \right|\). Find the...
Elements of a matrix is represented by aij=23i−j. Find the 2×2 matrix.
Solution
First express the 2×2 matrix in its standard form\left| {\begin{array}{*{20}{c}} {{a_{11}}}&{{a_{12}}} \\\ {{a_{21}}}&{{a_{22}}} \end{array}} \right|. Then calculate the elements of the matrix using the given formula aij=23i−j.
Complete step-by-step answer:
In mathematics, a matrix (plural matrices) is a rectangular array or table of numbers, symbols, or expressions, arranged in rows and columns. Example of a 2×2matrix is \left| {\begin{array}{*{20}{c}}
2&5 \\\
3&6
\end{array}} \right|.
The size of a matrix is denoted by the number of rows and columns that a matrix contains.
The elements of a matrix is denoted by aij, it means that aijis the element in the ith row and jth column.
Here it is mentioned that aij=23i−j
We have to find a 2×2 matrix.
So the matrix will be in the form \left| {\begin{array}{*{20}{c}}
{{a_{11}}}&{{a_{12}}} \\\
{{a_{21}}}&{{a_{22}}}
\end{array}} \right|
Now we have to calculate a11,a12,a21,a22 respectively.
aij=23i−j
So a11=23×1−1=22=1
Similarly a12=23×1−2=21, a21=23×2−1=25 and a22=23×2−2=24=2
So the required 2×2 matrix is \left| {\begin{array}{*{20}{c}}
{{a_{11}}}&{{a_{12}}} \\\
{{a_{21}}}&{{a_{22}}}
\end{array}} \right|
=\left| {\begin{array}{*{20}{c}}
{{a_{11}}}&{{a_{12}}} \\\
{{a_{21}}}&{{a_{22}}}
\end{array}} \right| = \left| {\begin{array}{*{20}{c}}
1&{\dfrac{1}{2}} \\\
{\dfrac{5}{2}}&2
\end{array}} \right|
The required 2×2 matrix is \left| {\begin{array}{*{20}{c}} 1&{\dfrac{1}{2}} \\\ {\dfrac{5}{2}}&2 \end{array}} \right|
Note: We should also remember various information of matrix regarding aij
For example: If a matrix is symmetric than we can say that aij=aji, whether if the matrix be skew symmetric then aij=−aji. For a null matrix aij=0.