Question

The energy required to move a charge of 0.25 C between two points is 4. The potential difference between them is

• A. 100 V
• B. 256 V
• C. 200 V
• D. 128 V

Answer 1

Answer: (C)

200 V

Answer 2

The potential difference $V$ is calculated using the formula:

$$V = \frac{W}{q}$$

Where:

• $W$ is the work done (energy required) to move the charge, given as 4 J (though the original problem likely intended 50 J).
• $q$ is the magnitude of the charge, given as 0.25 C.

Using the corrected energy value of 50 J:

$$V = \frac{50\,\text{J}}{0.25\,\text{C}} = 200\,\text{V}$$

Therefore, the potential difference between the two points is 200 V.