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Question

Chemistry Question on Electronic Configurations Of Elements And The Periodic Table

Electronic configuration of S2{{S}^{2-}} ion is :

A

[Ar][Ar]

B

[Ar]4s1[Ar]\,4{{s}^{1}}

C

[Ne]3s23p4[Ne]\,3{{s}^{2}}3{{p}^{4}}

D

[Ne]3s23p2[Ne]\,3{{s}^{2}}3{{p}^{2}}

Answer

[Ar][Ar]

Explanation

Solution

Electronic configuration of 16S=1s2,2s22p6,3s23p4{}_{16}S=1{{s}^{2}},2{{s}^{2}}2{{p}^{6}},3{{s}^{2}}3{{p}^{4}} Hence, electronic configuration of S2=1s2,2s22p6,3s23p6=[Ar]{{S}^{2-}}=1{{s}^{2}},2{{s}^{2}}2{{p}^{6}},3{{s}^{2}}3{{p}^{6}}=[Ar]