Electronic configuration of ( Cu^{ 2 + } ) ion is | Chemistry | SolveeIt

Electronic configuration of $Cu^{ 2 + }$ ion is

$[ Ar ] \, 4s^1 \, 3d^8$

$[ Ar ] \, 4s^0 \, 3d^8$

$[ Ar ] \, 4s^2 \, 3d^7$

$[ Ar ] \, 4s^0 \, 3d^9$

Answer

$[ Ar ] \, 4s^0 \, 3d^9$

Explanation

$Cu_{ 2 9 } : [ Ar ] 4s^1 \, 3d^{ 10}$
$Cu^{ 2 + } : [ Ar ] 4s^0 \, 3d^9$

Chemistry Question on d block elements