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Chemistry Question on Organic Chemistry- Some Basic Principles and Techniques

Electronegativity of carbon atoms depends upon their state of hybridisation. In which of the following compounds, the carbon marked with asterisk is most electronegative?

A

CH3??H2??overset∗CH2??H3CH_{3}??H_{2}??overset{*}{C}H_{2} ??H_{3}

B

$CH_{3} ?

C

CH3??H2??≡C∗HCH_{3} ??H_{2} ??\equiv\overset{*}{C}H

D

CH3??H2??H=C∗H2CH_{3} ??H_{2}??H = \overset{*}{C}H_{2}

Answer

CH3??H2??≡C∗HCH_{3} ??H_{2} ??\equiv\overset{*}{C}H

Explanation

Solution

The greater the ss character of the hybrid orbitals, the greater is the electronegativity. Thus, a carbon atom having an spsp hybrid orbital with 50%50\% ss character is more electronegative than those possessing sp2sp^{2} or sp3sp^{3} hybridised orbitals. The asterisk marked carbon in CH3??H2??≡C∗HCH_{3} ??H_{2} ??\equiv\overset{*}{C}H is spsp hybridised hence, it is most electronegative.