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Question: Electrolyte| \(\text{KCl}\)| \(\text{KN}{{\text{O}}_{3}}\)| \(\text{HCl}\)| \(\text{NaOAc}\)| \(\tex...

ElectrolyteKCl\text{KCl}KNO3\text{KN}{{\text{O}}_{3}}HCl\text{HCl}NaOAc\text{NaOAc}NaCl\text{NaCl}
(Scm2mol1){}_{\text{(Sc}{{\text{m}}^{2}}}{{\wedge }^{\infty }}{}_{\text{mo}{{\text{l}}^{-1}})}149.9145.0426.291.0126.5

Calculate HOAc{{\wedge }^{\infty }}_{\text{HOAc}} using appropriate molar conductance of the electrolytes listed above at infinite dilution in H2O{{\text{H}}_{2}}\text{O} at 25C25{}^\circ \text{C}.
A. 517.2
B. 552.7
C. 390.7N
D. 217.5

Explanation

Solution

The ratio of conductivity of an electrolyte and its molar conductance gives the molar conductance, which is denoted by m {{\wedge }_{\text{m}}}\text{ }. The molar conductance has SI unit, Siemens metre squared per mol (Sm2mol1)\text{(S}{{\text{m}}^{2}}\text{mo}{{\text{l}}^{-1}}).

Complete Answer:
-We have to calculate the molar conductance at infinite dilution for HOAc\text{HOAc} at a given temperature.
-so, firstly we will write the reaction between hydrochloric acid and NaOAc\text{NaOAc} i.e.
HCl + NaOAc  NaCl + HOAc\text{HCl + NaOAc }\to \text{ NaCl + HOAc}
-Now, for the calculating the molar conductance the formula will be written according to the reaction but the temperature will not
-Now, the formula of molar conductance at infinite dilution will be:
HOAc = NaOAc + HCl - NaCl ....(1)\wedge _{\text{HOAc}}^{\infty }\text{ = }\wedge _{\text{NaOAc}}^{\infty }\text{ + }\wedge _{\text{HCl}}^{\infty }\text{ - }\wedge _{\text{NaCl}}^{\infty }\text{ }....\text{(1)}
-Here, the molar conductance of sodium chloride is subtracted because molar conductance of sodium chloride is not asked i.e. to remove the sodium from sodium acetate and chlorine from hydrochloric acid.
-It is given in the question that the value of molar conductance of sodium acetate, hydrochloric acid and sodium chloride is 91.0, 426.2 and 126.5 respectively.
-Now, we will put these values in the equation (1) and we will get,
91 + 426.2 - 126.5 = 390.7 Scm2mol191\text{ + 426}\text{.2 - 126}\text{.5 = 390}\text{.7 Sc}{{\text{m}}^{2}}\text{mo}{{\text{l}}^{-1}}.
Therefore, option C is the correct answer.

Note: According to the theory of electrolysis, dissociation which was given by Arrhenius, if the electrolyte has completely dissociated then the value of molar conductance at infinite dilution will be minimum.