Question
Question: Electrolyte| \(\text{KCl}\)| \(\text{KN}{{\text{O}}_{3}}\)| \(\text{HCl}\)| \(\text{NaOAc}\)| \(\tex...
Electrolyte | KCl | KNO3 | HCl | NaOAc | NaCl |
---|---|---|---|---|---|
(Scm2∧∞mol−1) | 149.9 | 145.0 | 426.2 | 91.0 | 126.5 |
Calculate ∧∞HOAc using appropriate molar conductance of the electrolytes listed above at infinite dilution in H2O at 25∘C.
A. 517.2
B. 552.7
C. 390.7N
D. 217.5
Solution
The ratio of conductivity of an electrolyte and its molar conductance gives the molar conductance, which is denoted by ∧m . The molar conductance has SI unit, Siemens metre squared per mol (Sm2mol−1).
Complete Answer:
-We have to calculate the molar conductance at infinite dilution for HOAc at a given temperature.
-so, firstly we will write the reaction between hydrochloric acid and NaOAc i.e.
HCl + NaOAc → NaCl + HOAc
-Now, for the calculating the molar conductance the formula will be written according to the reaction but the temperature will not
-Now, the formula of molar conductance at infinite dilution will be:
∧HOAc∞ = ∧NaOAc∞ + ∧HCl∞ - ∧NaCl∞ ....(1)
-Here, the molar conductance of sodium chloride is subtracted because molar conductance of sodium chloride is not asked i.e. to remove the sodium from sodium acetate and chlorine from hydrochloric acid.
-It is given in the question that the value of molar conductance of sodium acetate, hydrochloric acid and sodium chloride is 91.0, 426.2 and 126.5 respectively.
-Now, we will put these values in the equation (1) and we will get,
91 + 426.2 - 126.5 = 390.7 Scm2mol−1.
Therefore, option C is the correct answer.
Note: According to the theory of electrolysis, dissociation which was given by Arrhenius, if the electrolyte has completely dissociated then the value of molar conductance at infinite dilution will be minimum.