Question

Electrolysis of dilute aqueous NaCl solution was carried out by passing 10 milli ampere current. The time required to liberate 0.01 mol of H2 gas at the cathode is: (1 Faraday =96500Cmol−1)

• A. (A) 9.65×104 sec
• B. (B) 19.3×104 sec
• C. (C) 28.95×104 sec
• D. (D) 38.6×104 sec

Answer 1

Answer: (B)

(B) 19.3×104 sec

Answer 2

Explanation:
Q=i×tQ=10×10−3×t2H2O+2e−→H2+2OH−To liberate 0.01 mole of H2, 0.02 Faraday charge is requiredQ=0.02×96500C∴0.02×96500=10−2×t⇒t=19.3×104 secHence, the correct option is (B).