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Question: Electrolysis of dil H2SO4 liberates gases at anode and cathode...

Electrolysis of dil H2SO4 liberates gases at anode and cathode

A

O2 & SO2 respectively

B

SO2 & O2 respectively

C

O2& H2 respectively

D

H2 & O2 respectively

Answer

O2& H2 respectively

Explanation

Solution

At anode: 2H2O→O2+4H++4e−2H_{2}O \rightarrow O_{2} + 4H^{+} + 4e^{-}

At cathode : 2H++2e−→H22H^{+} + 2e^{-} \rightarrow H_{2}