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Chemistry Question on GROUP 1 ELEMENTS

Electrolysis of brine gives a mixture of

A

\ceH2,Na,Cl2\ce{ H_2, Na, Cl_2}

B

\ceCl2,H2,NaOH\ce{Cl_2, H_2, NaOH }

C

\ceH2,O2,NaOH\ce{ H_2, O_2, NaOH}

D

\ceO2,Cl2,NaOH\ce{O_2, Cl_2, NaOH }

Answer

\ceCl2,H2,NaOH\ce{Cl_2, H_2, NaOH }

Explanation

Solution

In the electrolysis of brine (a NaCl)
Reaction at cathode : 2H(aq)++2e−−>H2(g) { 2H^+_{(aq)} + 2e^- -> H_{2(g)}}
Reaction at anode : 2Cl(aq)−−>Cl2(g)+2e− { 2Cl^- _{(aq)} -> Cl_{2(g)} + 2e^-}
Na+Na^+ and OH−OH^- ions remain in the solution.