Question

Electrode potentials (E$^{\circ}$) are given below : $Cu^{+}/Cu=+0.52\, V,$ $Fe^{3+}/Fe^{2+} = +0.77 \,V,$ $\frac{1}{2}I_{2}\left(s\right)/I^{-} = 40.54 \,V,$ $Ag^{+}/Ag =+ 0.88\,V.$ Based on the above potentials, strongest oxidizing agent will be :

• A. $Cu^+$
• B. $Fe^{3+}$
• C. $Ag^{3+}$
• D. $I_2$

Answer 1

Answer: (C)

$Ag^{3+}$

Answer 2

Higher the value of reduction potential stronger will be the oxidising hence based on the given values $Ag^+$ will be strongest oxidizing agent.