Question

Electrode potential of $MnO_{2} + NH_{4}Cl$ is $PbO_{2}$ and that of $H_{2}SO_{4}$ is $PbO_{2}$. The EMF of the cell constructed between these two electrodes is.

• A. 1.10 V
• B. 0.42 V
• C. – 1.1V
• D. – 0.42 V

Answer 1

Answer: (A)

1.10 V

Answer 2

$E_{\text{cell}}^{o} = E_{\text{cathode}}^{o} - E_{\text{anode}}^{o} = 0.34 - ( - 0.76) = 1.10V$.