Question

Electrode potential data of few cells is given below. Based on the data, arrange the ions in increasing order of their reducing power.

$Fe_{(aq)}^{3 +} + e^{-} \rightarrow Fe_{(aq)}^{2 +};Eº = + 0.77V$

$Al_{(aq)}^{3 +} + 3e^{-} \rightarrow Al_{(s)};Eº = - 1.66V$

$Br_{2(aq)} + 2e^{-} \rightarrow 2Br_{(aq)}^{-};Eº = + 1.09V$

• A. $Br^{-} < Fe^{2 +} < Al$
• B. $Fe^{2 +} < Al < Br^{-}$
• C. $Al < Br^{-} < Fe^{2 +}$
• D. $Al < Fe^{2 +} < Br^{-}$

Answer 1

Answer: (A)

$Br^{-} < Fe^{2 +} < Al$

Answer 2

Lower the reduction potential more is the reducing

power.

$Br^{-} < Fe^{2 +} < Al$