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Question

Physics Question on electrostatic potential and capacitance

Electric potential at any point is V=5x+3y+15z,V = - 5x + 3y + \sqrt {15 z}, then the magnitude of the electric field is

A

323\sqrt {2}

B

424\sqrt {2}

C

525\sqrt {2}

D

7

Answer

7

Explanation

Solution

Ex=rvrx=rrx(5x+5y+15z)=5E_{x}=-\frac{r v}{r x}=\frac{-r}{r x}(-5 x+5 y+\sqrt{15 z})=5
Ey=rvry=3Ez=15E_{y}=\frac{r v}{r y}=-3 E_{z}=-\sqrt{15}
Now, E=Eyx+Eyz+Ezz=7E=\sqrt{E_{y}^{x}}+E_{y}^{z}+E_{z}^{z}=7