Question
Physics Question on electrostatic potential and capacitance
Electric potential at any point is V=−5x+3y+15z,then the magnitude of the electric field is
A
32
B
42
C
52
D
7
Answer
7
Explanation
Solution
Ex=−rxrv=rx−r(−5x+5y+15z)=5
Ey=ryrv=−3Ez=−15
Now, E=Eyx+Eyz+Ezz=7