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Question

Question: Electric field strength due to a point charge of \(5\mu C\) at a distance of 80 cm from the charge i...

Electric field strength due to a point charge of 5μC5\mu C at a distance of 80 cm from the charge is

A

8×1048 \times 10^{4}N/C

B

7×1047 \times 10^{4}N/C

C

5×1045 \times 10^{4}N/C

D

4×1044 \times 10^{4}N/C

Answer

7×1047 \times 10^{4}N/C

Explanation

Solution

E=9×109.Qr2=9×109×5×106(0.8)2=7×104N/CE = 9 \times 10^{9}.\frac{Q}{r^{2}} = 9 \times 10^{9} \times \frac{5 \times 10^{- 6}}{(0.8)^{2}} = 7 \times 10^{4}N ⥂ / ⥂ C