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Question

Physics Question on Electric charges and fields

Electric field in a certain region is given by E=(Ax2i^+By3j^)\overrightarrow{ E }=\left(\frac{ A }{x^2} \hat{i}+\frac{ B }{y^3} \hat{j}\right) The SISI unit of AA and BB are :

A

Nm2C1;Nm3C1Nm ^2 C ^{-1} ; Nm ^3 C ^{-1}

B

Nm3C;Nm2CNm ^3 C ; Nm ^2 C

C

Nm2C;Nm3CNm ^2 C ; Nm ^3 C

D

Nm3C1;Nm2C1Nm ^3 C ^{-1} ; Nm ^2 C ^{-1}

Answer

Nm2C1;Nm3C1Nm ^2 C ^{-1} ; Nm ^3 C ^{-1}

Explanation

Solution

E=x2A​i^+y3B​j^​
[x2A​]=NC−1⇒[A]=Nm2C−1
[y3B​]=NC−1⇒[B]=Nm3C−1