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Question: Electric field at x = 10 cm is 100 V/m and at x = –10cm is – 100 V/m. The magnitude of charge enclo...

Electric field at x = 10 cm is 100 V/m and at x = –10cm is

– 100 V/m. The magnitude of charge enclosed by the cube of side 20 cm is-

A

8 e0

B

2 e0

C

3 e0

D

5 e0

Answer

8 e0

Explanation

Solution

fTotal =

E.a2 + E.a2 = ̃ 2E.a2 =

2 × 100 × (20 × 10–2)2 =

\ qin =8ε0\mathrm { q } _ { \text {in } } = 8 \varepsilon _ { 0 }