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Question

Physics Question on electrostatic potential and capacitance

Electric field and potential inside hollow charged conducting sphere are respectively where qq and rr are the charge and radius of given sphere

A

0,00,0

B

0,14πε0qr0, \frac{1}{4\pi\varepsilon_{0}} \frac{q}{r}

C

14πε0qr2,0 \frac{1}{4\pi\varepsilon_{0}} \frac{q}{r^{2}}, 0

D

14πε0qr2,14πε0qr \frac{1}{4\pi\varepsilon_{0}} \frac{q}{r^{2}}, \frac{1}{4\pi\varepsilon_{0}} \frac{q}{r}

Answer

0,14πε0qr0, \frac{1}{4\pi\varepsilon_{0}} \frac{q}{r}

Explanation

Solution

E=0E=0, inside a hollow conducting sphere VV= potential at any point inside = potential at the surface =q4πε0r =\frac{q}{4\pi\varepsilon_{0} r}.