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Question: Eight drops of mercury of same radius and having same charge coalesce to form a big drop. Capacitanc...

Eight drops of mercury of same radius and having same charge coalesce to form a big drop. Capacitance of big drop relative to that of small drop will be

A

16 times

B

8 times

C

4 times

D

2 times

Answer

2 times

Explanation

Solution

By using relation C=n1/3.cC = n^{1/3}.c ⇒ C=(8)1/3.c=2cC = (8)^{1/3}.c = 2c